Question

How many 88 ohm resistors(in parallel) are required to carry 15 A on 220 V line?
6
60
88
176
​

Answer 1

Explanation:

Let n be the required number of resistors.

Resistor R = 88 Ω

Equivalent resistance of parallel combination is

Req = R/n = 88/n Ω

V = I Req

220 = 15 x 88/n

n = 15 x 88/220

= 15 x 4/10

= 6