Physics, asked by abelmathewjohnson10c, 6 months ago

How many 88 Ω resistors ( in parallel ) are required to carry 5 A

on a 220 V line?

Answers

Answered by HarmanHarman5041

1

Answer:

2

Explanation:

I = V/R

5 = 220/R

R = 44ohm

let no of resistors in parallel = n

required resistance = 44 ohm

resistance of one resistor = 88 ohm

88/n = 44

n=2

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