Question

How many 88 Ω resistors ( in parallel ) are required to carry 5 A

on a 220 V line?​

Answer 1

Answer:

2

Explanation:

I = V/R

5 = 220/R

R = 44ohm

let no of resistors in parallel = n

required resistance = 44 ohm

resistance of one resistor = 88 ohm

88/n = 44

n=2