Chemistry, asked by Anonymous, 5 months ago

How many 90° bond angles
existed in the molecule
SF6?​

Answers

Answered by cathunney
1

Answer:

90 is the angle bond

Explanation:

SF6 is one angle

Answered by monisushmakavila
1

Answer:

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QuEsTiOn

I don't know

{\huge{\pink{\underline{\underline{Formula\ used}}}}}

Formula used

\begin{gathered}Loss=C.P.-S.P\\ Loss\ percent= \frac{Loss}{C.P} \times 100\end{gathered}

I

don't

know

the answer

{\huge{\pink{\underline{\underline{SoLuTiOn}}}}}

SoLuTiOn

Let the cost price of 1 toy be x.

Then,cost price of 12 toys is 12x

A/Q

Selling price of 15 toys=cost price of 12 toys=12x

So,selling price of 1 toy=\frac{12x}{15}

15

12x

=\frac{12x÷3}{15÷3}

15÷3

12x÷3

=\frac{4x}{5}

5

4x

\begin{gathered}Loss=C.P.-S.P\\ =x - (\frac{4x}{5})\\ = \frac{5x}{5} - \frac{4x}{5} \\ =\frac{x}{5}\end{gathered}

Loss

\begin{gathered}Loss percent= \frac{Loss}{C.P} \times 100\\ = \frac{ \frac{x}{5} }{x} \times 100\\ =\frac{x}{5x} \times 100\\ =\frac{1}{5} \times 100\\\end{gathered}

Losspercent=

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