Question

How many address bits are required for a 1024*8 memory?

Answer 1

Answer:

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Explanation:

You need log2(n) bits to address n bytes. For example, you can store 256 different values in an 8 bit number, so 8 bits can address 256 bytes. 210 = 1024, so you need 10 bits to address every byte in a kilobyte