Question

How many address lines are required by the memory that contain 16k words?

Answer 1

Answer:

If your RAM is organized as 32 bit words, then you need 4096+16*2^4 or 4352 addresses, if for 64 bit words, 2048+16*2^4 or 2304 addresses. In a system each byte is addressed individually. There are 1024 bytes in one k byte. A 16k ram would therefore need 1024*16 = 16384 addresses.

Answer 2

The address lines are required by the memory that contains 16k  word is addresses.$1024*16 = 16384$

Explanation:

Always remember a simple trick for address line calculation for a specific memory capacity;

$10$ Address lines can access $1K$of memory.

if we increase only 1 address line, the memory capacity increases twice than before.

so now 11 address lines can access$2k$ memory.

Now simply add 1 address line and twice the memory capacity.

it goes like this->

10 address lines - $1K$ memory

11 address lines -$2K$ memory

12 address lines - $4K$ memory

13 address lines - $8K$ memory

14 address lines -$16K$ memory

15 address lines -$32K$ memory

16 address lines - $64k$memory

17 address lines -$128K$memory

18 address lines - $256k$ memory

19 address lines - $512k$ memory

20 address lines - Now 1Mega Bytes memory -$1M$.

Answer:

address lines are required by the memory that contains 16k words$1024*16 = 16384$.