Question

How many Al³+ ions are there in 204g of aluminium oxide​

Answer 1

Explanation:

option c

Now, 27 g of aluminium has ions = 6.022 × 10^23 aluminium ions. So, 0.027 g of aluminium has ions = 6.022 × 10^23 / 27 × 0.027. Thus, the number of aluminium ions (Al³+) in 0.051 gram of aluminium oxide is 6.022 × 10^20.