Question

How many aluminium atoms are present in an aluminium wire of 8.1 gram

Answer 1

Answer:

The aluminium atoms are present in an aluminium wire of 8.1 gram are 1.8066 × 10²³ atoms

Explanation:

We first calculate the moles of Aluminum in 8.1 grams

Molar mass of Aluminum = 27 g/mole

Moles of Aluminum = mass of Aluminum / Molar mass

Moles = 8.1/27 = 0.3 moles

Avogadros constant:

1 mole = 6.02214076×10²³ atoms

Therefore, the atoms of aluminum in 8.8 gram of aluminum wire is:

0.3 × 6.02214076×10²³ = 1.8066 × 10²³ atoms

Answer 2

1.8066 × 10²³ atoms

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