Question

How many am I?
1. I am a three digit number
2. I am an odd number
3 I am divisible by 5
4. Each of my digits is different.
5. My digits add up to 8.
6. The tens digit is smaller than
the hundreds digit.
7. I am less than 300.
8. I have only one even digit
Try to solve using the given order​

Answer 1

Answer: Only one number i.e 215

Answer 2

Answer: 215

1. 3 digit number

(So the number is 3-digit)

Consider it as (*)(*)(*)

2. Odd number

(So the last digit must be 1,3,5,7 or 9  as odd numbers must have 1,3,5,7 or 9  in it's last digit)

Consider it as (*)(*)(1/3/5/7/9)

3. Divisible by 5

So last digit must be 5 (as it is also odd.)

Consider it as (*)(*)(5)

4. Each digit different:

(So The other digits are not 5 and they both differ)

5. Digits add up to 8:

As the last digit is 5

The sum if other two is 3(i.e. 8-5 )

The pair could be (3,0) or (2,1)

6. Tens digit smaller than hundreds digit

So it must be 305 or  215 in which the ten's digit is smaller than hundred's digit

7. Less than 300

The number which is less than 300 is 215

Hope this helps

Please mark me as the brainliest