Question

how many amperes would be needed to produce 60.0 gram of magnesium during the electrolysis of molten MgCl2 in 2 hours ...



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Answer 1

Given:

Mass of magnesium = 60 gm

Time = 2 hrs = 120 seconds

To Find:

Amount of electricity needed for this electrolysis.

Calculation:

- For Magnesium:

M.wt = 24 gm

n = 2

F = 96500 C/mol

- Applying Faraday's first law of electrolysis, we have:

w = (I × t × M.wt) / (n × F)

⇒ I = (w × n × F) / (t × M.wt)

⇒ I = (60 × 2 × 96500) / (2 × 60 × 60 × 24)

⇒ I = 96500/1440

⇒ I = 67.014 A

- So, 67.014 A current is required to produce the required amount of magnesium.