Question

How many amps current can be pushed through a 30.0 Ω resistor by a 12.0 V battery?

Answer 1

Answer:

Va-Vb= i × R

12=i ×30

I = 12/30=2/5 Ampere

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Answer 2

Hey user

Given :-

•R = 30.0Ω,And

•V = 12.0v

By ohm's law. we have ,

v = IR

=> 12.0v = I × 30.0Ω

=> I = 12/30

thus , I = 0.4Ampere