Question

how many arguments pass in fopen() c language
tell me answer fast..​

Answer 1

There are two arguments passed in fopen() c language.

1. const char* filename

2. const char* mode

Explanation:

fopen() function in C:

The fopen() function is used in C language to open a stream that links to a file.

Declaration:

FILE *fopen (const char *file_name, const char *mode)

file_name: It is the given file name that you want to open.

mode: The operation mode can be like read, write etc.

Example: fopen("F:\\cprogramming\\newproject.txt","w");

Answer 2

The c language fopen() takes two arguments.  

Explanation:

The C library function "FILE * fopen(const char * filename, const char * mode)" opens the filename indicated by the filename using the specified mode.

The following is the declaration for fopen() function.

• "FILE *fopen(const char *filename, const char *mode)"
• This has 2 parameters filename, mode as its arguments.
• filename - This is the C string holding the filename to be opened.
• mode - This is the C string holding a file access mode.
• This function returns a FILE pointer. Otherwise, 'NULL is returned' and the 'global variable' errno is set to indicate the error.

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