How many ato
ms are present in 1.6g of methane ch4
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1.6÷16×6.023×10^23 your ans will
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Answer:
hey mate ....here is u r answer 0.4 or 2.4 × 10 ^23
Explanation:
no of atoms = given wt / gmw × Na × atomicity
= 1.6 / 16 ×Na × 4 ( ch4 = 1 2+ 4 =16 (gmwt )
= 0.4.... (atomicity = 1 + 3 =4)
( or )
= 1.6 / 16 × 6.023 × 10 ^23 × 4
= 2.4 × 10 ^23 ...
hope its help u.... .................
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