Question

how many atom and molecules of sulphur present in 64.0 g of sulphur​

Answer 1

Answer:

How many atoms and molecules of sulphur are present in 64.0 g of sulphur (S8)? ∴ 64 g of sulphur will contain=6.022×1023×64256=1.506×1023 molecules.

Answer 2

${\underline{\underline{\mathfrak{\purple{Calculation}}}}}$

Molar mass of sulphur $\sf{(S_{8})}$ :-

$\longrightarrow\:\:\bf{8 \times 32}$

$\longrightarrow\:\:\bf{256\:g/mol}$

No. of moles of $\sf{S_{8}}$ :-

$\longrightarrow\:\:\bf{\dfrac{64}{256}}$

$\longrightarrow\:\:\bf{0.25}$

No. of molecules :-

$\longrightarrow\:\:\bf{0.25\times 6.022\times 10^{23}}$

$\longrightarrow\:\:\bf\green{1.50\times 10^{23}\: molecules}$

No. of s - atoms :-

$\longrightarrow\:\:\bf{1.50\times 10^{23}\times8}$

$\longrightarrow\:\:\bf\green{1.20\times 10^{23}}$