Question

How many atom are present in 320 Fe2O3 also find the no of moles in 44.8 litr of the gas at NTP?

Answer 1

Hello Mate!

So your question is

"How many atom are present in 320g of Fe2O3?"

So, first we will calulate molecular mass of Fe2O3 = ( 56 × 2 + 16 × 3 ) u or g/mol

= 160 g/mol

Now, number of moles = W in g / W in g/mol

= 320 g / 160 g/mol

= 2 moles

So, no. of atoms = No. of moles × avagrado no.

= 2 × 6.022 × 10²³

= 12.044 × 10²³

= 1.2044 × 10¹ × 10²³

=> 1.2 × 10²⁴ atoms

Now, "Find the no of moles in 44.8 litr of the gas at NTP?"

Now, in NTP condition 22.4 liters are holded in = 1 mole

Then 1 liter will be holded in = 1/22.4 moles

Them 44.8 liters will be holded in = 1/22.4 × 44.8

= 2 moles

=> Hence two moles is answer.

Have great future ahead!