Question

how many atom in 1.×10^-9gram of lead​

Answer 1

Answer:

2.91 x 10^12 atoms.

Explanation:

1 mol of Pb = 207.2g  

1E-9 / 207.2 = 4.83E-12  

4.83E-12 x 6.02E23 = 2.91E12  

So 2.91 x 10^12 atoms.