How many atoms and molecules are present in 124 g of p4?(p=31)
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Answer:
24.092x 10^23
Explanation:
number of moles of phosphorus molecules = 124/124 = 1 mole. One mole contains 6.023 x 10 ^ 23 particles. = 24.092x 10^23 atoms of phosphorus.
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24.092*10^23
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