Question

How many atoms and molecules of sulfur are present in 64 g of sulfur (S8)?

Answer 1

Answer:

Av- 6.022 X 10²³

B.O - bond oder

1 mol of S8 (sulfur ) - (B.O X Av)

[1 mol of S8 = molar mass of S8 ]

there for 1 g of S8 = (B.O X Av) / (molar mass of S8)

so, 64g of p = 64 (8 X Av) /(molar mass of S8)

= 1.20 X 10^24 atoms.

Hence, 64 g of S have 1.20 X 10^24 atoms.