Question

How many atoms and molecules of sulphur are present in 64.0 g of sulphur {(S8​

Answer 1

Answer:

This is a question of moles testing the concept of Avogadros constant.

We begin by getting molar mass of S₈.

Molar mass of one Sulphur = 32g/mol

Molar mass of S₈ = 32 × 8 = 256g /mol

Moles = mass / molar mass

Moles = 64/256 = 0.25moles

AVOGADROS CONSTANT :

1 mole = 6.02 × 10²³ atoms

The number of atoms in S₈ :

6.02 × 10²³ × 0.25 = 1.505 × 10²³ atoms.

The answer : 1.505 × 10²³ atoms

Answer 2

Explanation:

mole of sulphur in 64.0g is 64/32 = 2

thus moles is 2

atoms and molecules in it is 2 x avagadro number

= 2 x 6.022 x 10²³

= 12.044 x 10²³

hope this will help you