how many atoms and molecules of sulphur are present in 64 g of s8
Answers
Answered by
222
This is a question of moles testing the concept of Avogadros constant.
We begin by getting molar mass of S₈.
Molar mass of one Sulphur = 32g/mol
Molar mass of S₈ = 32 × 8 = 256g /mol
Moles = mass / molar mass
Moles = 64/256 = 0.25moles
AVOGADROS CONSTANT :
1 mole = 6.02 × 10²³ atoms
The number of atoms in S₈ :
6.02 × 10²³ × 0.25 = 1.505 × 10²³ atoms.
The answer : 1.505 × 10²³ atoms
We begin by getting molar mass of S₈.
Molar mass of one Sulphur = 32g/mol
Molar mass of S₈ = 32 × 8 = 256g /mol
Moles = mass / molar mass
Moles = 64/256 = 0.25moles
AVOGADROS CONSTANT :
1 mole = 6.02 × 10²³ atoms
The number of atoms in S₈ :
6.02 × 10²³ × 0.25 = 1.505 × 10²³ atoms.
The answer : 1.505 × 10²³ atoms
Answered by
72
molar mass of one sulphure = 32 g/mol
molar mass of s8 = 32* 8= 256g/mol
moles = 64/256 = 0.25 moles
AVOGADRO CONSTANT :
1 mole = 6.02 *10 ^23 * o.25
= 1.505*10^23 atoms ANSWER
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