Chemistry, asked by rawatshreya022, 1 year ago

how many atoms and molecules of sulphur are present in 64 g of s8

Answers

Answered by danielochich
222
This is a question of moles testing the concept of Avogadros constant.

We begin by getting molar mass of S₈.

Molar mass of one Sulphur = 32g/mol

Molar mass of S₈ = 32 × 8 = 256g /mol

Moles = mass / molar mass

Moles = 64/256 = 0.25moles

AVOGADROS CONSTANT :

1 mole = 6.02 × 10²³ atoms

The number of atoms in S₈ :

6.02 × 10²³ × 0.25 = 1.505 × 10²³ atoms.

The answer : 1.505 × 10²³ atoms

Answered by sanskarsaurabh
72

molar mass of one sulphure = 32 g/mol

molar mass of s8 = 32* 8= 256g/mol

moles = 64/256 = 0.25 moles

AVOGADRO CONSTANT :

1 mole =  6.02 *10 ^23 * o.25

           = 1.505*10^23  atoms    ANSWER

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