How many atoms and molecules of sulphur are present in 64g of sulphur
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Answer:
6.02 × 10²³ × 0.25 = 1.505 × 10²³ atoms.
Answered by
0
Answer:
This is a question of moles testing the concept of Avogadros constant.
We begin by getting molar mass of S8.
Molar mass of one Sulphur = 32g/mol
Molar mass of S8 = 32 x 8 = 256g/mol
Moles = mass / molar mass
Moles = 64/256 = 0.25moles
AVOGADROS CONSTANT :
1 mole = 6.02 × 10²³ atoms
The number of atoms in S8 :
6.02 × 1023 × 0.25 = 1.505 × 102³ atoms. 23
The answer : 1.505 x 1023 atoms
The answer : 1.505 x 1023 atoms23
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