Chemistry, asked by anjanamanoj626, 6 days ago

How many atoms and molecules present in 180g water?​

Answers

Answered by Rajkd180203
6

Answer:

1 mole of water = 18g

? mole of water = 180 g

180/18 = 10 mole

No of molecules:

1 mole = 6.02 × 10^23 molecules

10 moles = ? molecules

6.02 × 10^23 × 10 = 6.02 × 10^24 molecules.

No of atoms:

1 molecule of H2O = 3 atoms

molecules = ? Atoms

3 × 6.02 × 10^24 = 18.06 × 10^25 atoms

Answered by jewariya13lm
5

Answer:

The molecules in 180g water = 6.02 × 10²⁴

The atoms in 180g water = 1.806 × 10²⁵

Calculation:

1 mole of water of molecules = 18g

x moles of water of molecules = 180g

⇒ 180g × 1 = 18g × x

\frac{180}{18} = x

x = 10 mol of water

I mole of water molecules = 6.02 × 10²³

10 mole of water molecules = x

⇒ 1 × x =  (6.02 × 10²³) × 10

x = 6.02 × 10²⁴ molecules of water

1 molecule of water = 3 atoms

6.02 × 10²⁴ molecules of water = x atoms

⇒ 3 × (6.02 × 10²⁴) = 1 × x

= 1.806 × 10²⁵ atoms of water.

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