Question

how many atoms are contained in 25 g of nabr​

Answer 1

Explanation:

no.of mol = 25/102.894 = 0.242

no of atoms = 0.242×2×6.022×10^23

= 2.91×10^23

Answer 2

Given: 25g of sodium bromide.

To find: number of atoms in 25g of sodium bromide.

Step-by-step method:

Step 1 of 2

The molecular mass of $NaBr$ is $102.89g/mol$.

1 mole of $NaBr$ contains $2*6.022*10^{23}$ atoms.

Number of moles of sodium bromide are:

$n=\frac{givenmass}{molarmass} \\n=\frac{25}{102.89} \\n=0.2429$

Step 2 of 2

$0.2429 mol$ of sodium bromide is:

$0.2429 mol$ of $NaBr$ contains :

$0.2429*2*6.022*10^{23}\\=2.925*10^{23}$

25g of NaBr contains $2.925*10^{23}$ number of atoms.