Question

how many atoms are in 27.72 amu of beryllium

Answer 1

Answer:

Molar mass of Be = 9.012182 g/mol

so by this molar mass u can easily find the number of atoms

Answer 2

Answer:

1.915 x 10^26 beryllium atoms

Explanation:

given mass = 27.72 amu

mass of one Be atom = 9amu

no of moles of Be=27.72÷9=3.08

now,

no of atoms = no of moles ×na

= 3.08×6.022×104^23

1.915×10^26 atoms

( 1 mole = na atoms )