how many atoms are in 3.58 mol c2h6
Answers
Answered by
0
Explanation:
In 1 mole,
no. of C atoms =2 × 6.022 × 10^23
no. of H atoms = 6 × 6.022 × 10^23
Therefore,
in 3.58 moles,
no. of C atoms = 2 × 6.022 × 10^23 × 3.58 = 43.11752 × 10^23
no. of H atoms = 6 × 6.022 × 10^23 × 3.58 = 129.34256 × 10^23
Total no. of atoms = 10^23 ×(43.11752 + 129.34256)
= 172.46008 × 10^23
Similar questions