Question

how many atoms are in 48 gram helium
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Answer 1

Answer:

We know by Avogadro number that, 6.023 x 10^(23) no. of atoms of Helium make 1 mole that is equivalent to molar mass of Helium approximately 4 grams. Thus, 6.023 x 10^(24) atoms of Helium = (1/(6.023 x 10^(23) ) x 6.023 x 10^(24) moles = 10 moles.

Answer 2

Answer:

We know by Avogadro number that, 6.023 x 10^(23) no. of atoms of Helium make 1 mole that is equivalent to molar mass of Helium approximately 4 grams. Thus, 6.023 x 10^(24) atoms of Helium = (1/(6.023 x 10^(23) ) x 6.023 x 10^(24) moles = 10 moles.

Explanation:

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