How many atoms are in 54 g of Am?
Answers
Answered by
0
Answer:
Explanation:
the mass of Am aka Americium is 243g
1 mole of Am has 243 g
number of moles = given mass / atomic mass
= 54/243
= 0.22222
= 0.22 (approx.)
number of atoms = 0.22 * 6.022 * 10²³
= 1.32484 * 10²³
= 1.325 * 10²³
Similar questions