How many atoms are present in 0.25 mole of cl
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1.204e24 are present
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Answer: The number of atoms in 0.25 moles chlorine is found to be 3.011 × 10^23.
Explanation:
It can be solved as follows:
Number of atoms present in 1 mole of chlorine = 6.023 × 10^23 × 2
It is multiplied by 2 because one mole of chlorine contains two atoms ( Cl2)
Therefore, number of atoms present in 0.25 moles of chlorine = 6.023 × 10^23 × 2 × 0.25
which gives resultant as 3.011 × 10^23
The number of atoms which is present in 0.25 moles of chlorine is 3.011 × 10^23.
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