Question

how many atoms are present in 1.7g of ammonia​

Answer 1

Answer:

∴ 1.7 g of the ammonia contains (6.022 × 10²³) × 1.7/17 atoms. Now, 1 atom of the Ammonia contains 7 + 3 electrons = 10 electrons. ∴ 6.022 × 10²² atoms of the Ammonia contains 10 × 6.022 × 10²² electrons. Hence, the number of the electrons in 1.7 g of the Ammonia is 6.022 × 10²³ electrons.