Question

​how many atoms are present in 10g og o

Answer 1

1.6856 ×1023 atoms of oxygen

Explanation:

The question is incomplete. We have to find out the no. of atoms of oxygen in 10 g of water.

First we need to find out moles of water

Moles = mass / molar mass

mole of water = 10 /(1.008*2+16) = 10 /18 = 0.56

Now, as we know 1 mole contains 6.022 × 10 ^23 atoms or molecules  

Now from the formula we know, 2 mole of water contains 1 mole of oxygen

then moles of oxygen in 10g of water = 0.28

atoms of oxygen  in 10g of water  = 0.28 * 6.022 × 10 ^23  =  1.6856 ×1023 atoms of oxygen