Question

How many atoms are present in 142 grams of chlorine?

Answer 1

We know that,

The number of atoms = \frac{given mass}{molar mass}

molarmass

givenmass

× Avogadro number

Here,

Given mass = 142 g

We know that,

Molar mass of chlorine = 35·5 u

Avogadro number = 6·022×10²³

Therefore,

Number of atoms = \frac{142}{35·5}

35⋅5

142

× 6·022×10²³

= 4× 6·022×10²³

= 24·08×10²³

The number of atoms present in 142 grams of chlorine is 24·08×10²³

Answer 2

Answer:

24.092×10^23

Explanation:

please mark me as brainlist