Question

How many atoms are present in 2.50 mol of copper metal? (A) 1.5 ×1023 atoms (B) 4.5 ×1024 atoms (C) 1.5 ×1024 atoms (D) 4.5 ×1023 atoms

Answer 1

Given:

Moles of Copper  =2.5 mol

Solution:

From Avogadro's Law:

No. of atoms in 1 mole of any atom = $\sf{6.022 \times 10^{23}}$

$\sf{\therefore Atoms \:present \:in \:2.5 \:moles \:of \:copper=2.5 \times 6.022 \times 10^{23}}$

$\sf{Atoms = 15.055 \times 10^{23}}$

$\sf{ 15.055 \times 10^{23} \approx 1.5 \times 10^{24}}$

Therefore ,$\sf{ 1.5 \times 10^{24}}$ [approx] molecules are present in 2.5 mol of copper metal