Question

how many atoms are present in 20g of Na2CO3?

Answer 1

(i) Number of moles (n)=

molar mass of SO

3

mass of SO

3

=

80gmol

−1

20g

=0.25mol

(ii) Number of molecules of SO

3

= number of moles × Avogadro number

=0.25×6.023×10

23

=1.5×10

23

(iii) SO

3

is tetra-atomic. Hence, number of atoms present in 20g of SO

3

=1.5×10

23

×4=6×10

23

atoms

Answer 2

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                          ❤Answer️❤

= 6.86 X 1023 atoms.

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