Question

How many atoms are present in 23 gramm of Na and 32 gram of S? Name the number​

Answer 1

Explanation:

no. of mole in 23gm Na= 1 mole

so, no. of atom is 1*6.02 10^23 atoms

Answer 2

• Answer:

1. Atomic mass of Na = 23

then no of moles = 23/23 = 1 mole.

then No of Na atoms in 23g of Na = 1×6.022×10²³ atoms.

2. S have atomic mass = 32

no of moles of S = 32/32 = 1 mole

then no of atoms Of S in 1 mole of S = 1×6.022×10²³ atoms of S

formula for no of atoms = given mass/molecular mass.

hope it helos....