Question

how many atoms are present in 360g of gl​

Answer 1

Answer___

Glucose(C6H12O6) molecular mass is 12×6+1×12+16×6=72+12+96=180 g/mol

1 mole= 6.022× 10 to the power 23 (Na is Avogadro no.) 360g = 2 mol

then 180= Na then 360=Na/180×360 atoms

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