Question

How many atoms are present in 4.25 grams of NH3?
Please explain the answer.
Please explain by unitary method.

I will definitely mark the better answer as brainliest.
Thank you. ​

Answer 1

Answer: 1.5055*10^23molecules

Explanation:

17g of ammonia ---> 1mol

17g of ammonia ---> 6.022*10^23molecules

1g of ammonia ---> 6.022*10^23/17molecules

So,

4.25g of ammonia ---> 6.022*10^23*4.25/17molecules

4.25g of ammonia ---> 1.5055*10^23molecules