Question

how many atoms are present in 44g of CO2

Answer 1

No. of Atoms

= Given mass/ Molar Mass

Given Mass = 44g

Molar Mass

= C + O x 2

= 12 + 16 x 2

= 12 + 32

= 44g

No. of Atoms

= 44/44

= 1 Mole.

Now , 1 Mole contains 6.022 x 10^23 Atoms

So, 1 mole of carbon will have

6.022 x 10^23 particles