Question

how many atoms are present in 48.0g of H2SO4?​

Answer 1

Since u are asking about H2SO4, it is not the atom the question will ask it will be molecules.

Molar mass of H2SO4 = 2*1 + 32 + 4*16

= 98g

According to Avogadro's Law,

1 mole of H2SO4 i.e. 98g contains 6.022*10^23 molecules

therefore,

molecules present in 48 g are= 48/98*6.022*10^23 = 2.95*10^23 molecules.

Answer 2

Answer:

Molar mass of H2SO4 = 98g

Given mass = 48g

No. of moles = given mass/Molar mass

= 48/98 =0.489

1 mole contains 6.022 * 10^23 atoms

so 0.489 moles contain 0.489*6.022 * 10^23 atoms = 2.944*10^23