Question

How many atoms are present in 6.4 gram SO2?​

Answer 1

Answer:

Weight of S =6.4 g

Atomic weight of S =32 g/g atom

Number of gram atoms of S =

32 g/gatom

6.4 g

=0.2 gram atoms.

The Avogadro's number is 6.023×10

23

atoms/ g atom

The number of atoms of S =0.2 gram atoms ×6.023×10

23

atoms/ g atom

=1.2×10

23

atoms