HOW many atoms are present in 7.1 grams of chlorine gas
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Answer:2.408×10^23
Explanation:
no. of moles in Cl2 = 7.1÷35.5=0.2
no. of atoms = n× f× Avagadro's no.
= 0.2 ×2×6.02 ×10^23
= 2.408 × 10^23
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