Question

how many atoms are present in 9.0g​

Answer 1

Answer:

So 9.0 gram of Al will contain=9/26.998= 0.333 moles of Al. No. Of atoms of Al in 9 gram = 0.333× Avogadro no. =0.333×6.022×10^23=2.005×10^23 atoms.

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