how many atoms are present in 9.0g of aluminum and 0.8g of iron given atomic mass of aluminum 27 amu and Fe 56 amu
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Answer:
it can be find only by Avogadro's Number i.e. 6.02 ×10^23
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Explanation:
Moles of atoms present in 9 grams of aluminium is 0.33 moles. mole of a substance contains 6.022×10 atoms/molecules so 0.014324 moles will contain 0.014324×6.022×10 atoms.
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