Question

how many atoms are present in 9.0gof aluminum​

Answer 1

So 9.0 gram of Al will contain=9/26.998= 0.333 moles of Al. No. Of atoms of Al in 9 gram = 0.333× Avogadro no. =0.333×6.022×10^23=2.005×10^23 atoms.

Answer 2

Answer:

So 9.0 gram of Al will contain=9/26.998= 0.333 moles of Al. No. Of atoms of Al in 9 gram = 0.333× Avogadro no. =0.333×6.022×10^23=2.005×10^23 atoms.