Question

How many atoms are present in a (nh4)2so4molecule?

Answer 1

Answer:

Explanation:

(NH4)2SO4 molecule

Molar mass = (14+4)*2+32+64=132 amu

We have to just one molecule of The given compound

So we can calculate by just adding the no. Of atoms of each element in the compound

N=2,

H=8,

S=1,

O=4

=2+8+1+4=15

Thank you