Question

How many atoms are present in the following compounds?
i) 8 g of O2
ii) 4 g of CH4
i) 16 g of S8 molecules​

Answer 1

Answer:

1) 12g o3

2) 64g mol^-1

3) given that,

mass of S8 weight=16g

Molar mass of S8, mass=256g/mol

Therefore number of moles (n) =w÷M=16g÷256g/mol =0.0625 mol.

Therefore number of moles, N=n*Na

=0.0625*6.022*10^23

=3.76375*10^22 molecules