How many atoms are present in the following compounds?
i) 8 g of O2
ii) 4 g of CH4
i) 16 g of S8 molecules
Answers
Answered by
1
Answer:
1) 12g o3
2) 64g mol^-1
3) given that,
mass of S8 weight=16g
Molar mass of S8, mass=256g/mol
Therefore number of moles (n) =w÷M=16g÷256g/mol =0.0625 mol.
Therefore number of moles, N=n*Na
=0.0625*6.022*10^23
=3.76375*10^22 molecules
Similar questions