how many atoms are required to prepare 60 g of hno3
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Molecular wt of HNO3 is 1+14+3*16 = 63
60/63 = no of moles = 0.952380952
0.952380952 * Avogadro’s no = no of molecules = 5.7142857x10^23
5.7142857x10^23 x no of atoms in one molecule = number of atoms = 2.8571429x10^24 atoms
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