Question

How many atoms are required to prepare 60 grams of HNO3​

Answer 1

Reffer the achievement

Data:

• Mass of HNO3 = 60 grams.
• Molar mass of HNO3 = 63 grams.

To find:

• Number of atoms = ?

Solution:

First we have to find the number of moles then we have to find the number of molecules and then the number of atoms can be found.

so first,

$\implies{ \mathtt{n.o \: of \: moles = \frac{mass}{molar \: mass} }} \\ \implies{ \frac{60}{63} } \ \\ \implies{{0.9523}}$

Then,

$\implies \tt{n.o \: of \: molecules{ = n.o \: of \: moles \times N_A}} \\ \implies{0.9523 \times 6.02 \times {10}^{23} } \\ \implies{5.733 \times {10}^{23} }$

Now ,

Number of atoms = ?

HNO3 has five atoms in a molecule.

So,

$\implies{ \tt{n.o \: of \: atoms}} = 5.733 {10}^{23} \times5 \\ \implies28.66 \times {10}^{23} \\ \implies2.866 \times {10}^{1} \times {10}^{23} \\ \implies{2.866 \times {10}^{24} }$

Therefore,number of atoms is 2.866×10²⁴.

Answer 2

Answer:

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