Chemistry, asked by dharani925, 16 days ago

how many atoms are there in 12.5 moles of helium

Answers

Answered by rksevices

0

Explanation:

1 mole Of Helium = Weight of Helium/4Weight of Helium = 1*4 = 4 grams 1 mole of Helium contains 6.023*10²³ (Avogadro number) atoms

Answered by 12345ashishash

0

1 mole Of Helium = Weight of Helium/4Weight of Helium = 14 = 4 grams 1 mole of Helium contains 6.02310²³ (Avogadro number) atoms.

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