How many atoms are there in 21g of mgco3
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Answered by
2
Answer:
Explanation:
we have 21 g of magnesium carbonate
MgCO3=21g
first we have to no. of moles
molar mass of mgco3=24+28*3
=24+84=108g
no. of moles =21/108=0.19 moles
here we get 0.19 moles of MgCO3
therefore Mg also have 0.19 moles
no. of molecules of Mg=0.19*6.022*10^23
=1.144*10^23 molecules
Answered by
3
Explanation:
we have 21 g of magnesium carbonate
MgCO3=21g
first we have to no. of moles
molar mass of mgco3=24+28*3
=24+84=108g
no.of moles =given mass/molar mass
no. of moles =21/108=0.19 moles
here we get 0.19 moles of MgCO3
therefore Mg also have 0.19 moles
no. of molecules of Mg=0.19*6.022*10^23
=1.144*10^23 molecules
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