Question

How many atoms are there in 21g of mgco3

Answer 1

Answer:

Explanation:

we have 21 g of magnesium carbonate

MgCO3=21g

first we have to no. of moles

molar mass of mgco3=24+28*3

=24+84=108g

no. of moles =21/108=0.19 moles

here we get 0.19 moles of MgCO3

therefore Mg also have 0.19 moles

no. of molecules of Mg=0.19*6.022*10^23

=1.144*10^23 molecules

Answer 2

Explanation:

we have 21 g of magnesium carbonate

MgCO3=21g

first we have to no. of moles

molar mass of mgco3=24+28*3

=24+84=108g

no.of moles =given mass/molar mass

no. of moles =21/108=0.19 moles

here we get 0.19 moles of MgCO3

therefore Mg also have 0.19 moles

no. of molecules of Mg=0.19*6.022*10^23

=1.144*10^23 molecules