How many atoms are there in 23g of sodium atom
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Answer:
There are 6.02*10^23 atoms in each mole (Avagadro no.) That is x moles * avagadro no. According to that, in 23 grams of sodium we have 6.02*10^23 atoms of Na.
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Answer:
mass Na atom = 22.99 g Na /mole×1 /mole/6.023×102 power 3 atoms =3.817×10 ki power negetive 23g
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