Question

how many atoms are there in 240 amu of mg​

Answer 1

Hey mate !!

Here's the answer !!

We know that, 

1 u = 1 g 

Hence Magnesium has 96 g.

Hence, Given Mass is 96 g

We know that,

Number of moles = Given Mass / Molecular Mass

=> Number of moles = 96 g / 24 g = 4 Moles

We know that ,

1 mole = 6.022 × 10²³ atoms

So 4 moles will have 4 × 6.022 × 10²³

=> 4 moles will have 24.08 × 10²³ atoms.

Hence the Magnesium will contain 24.08 × 10²³ atoms.

Hope my answer helped !!

Cheers !!

Answer 2

240amu of Mg contains $6.023×10^{24}$ atoms.

Given: 240 amu of Mg.

To find: We have to find the number of atoms.

Solution:

The molecular weight of Magnesium is 24 grams.

The given mass of Mg is 240amu.

We know that 1 amu is equal to 1 gram.

So, 240amu will be equal to 240 grams.

The number of moles of magnesium is-

$\frac{240}{24} = 10$

Now 1 mole of Mg contains$6.023×10^{23}$ atoms.

So, 10 moles of Mg will contain

$6.023 \times {10}^{23} \times 10 = 6.023 \times {10}^{24}$

Thus 240amu of Mg contains $6.023×10^{24}$ atoms.